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Jul 25, 2010 · It's probably obvious to most, but the correct way to simulate the problem is to generate two unequal random numbers in (0,1) and treat them as your cutting points.
Nov 24, 2020 · The condition that x, y, and z 'will form a triangle' is equivalent to the three conditions: x + y > z, x + z > y, and y + z > x. The subset of T where (x,y,z) satisfy these three …
Feb 28, 2020 · “A square is a polygon made up of four line segments, out of which, length of three line segments are equal to the length of fourth one and all its angles are right angles”.
May 17, 2022 · You'll need to complete a few actions and gain 15 reputation points before being able to upvote. Upvoting indicates when questions and answers are useful. What's reputation …
Monocarp wants to draw the segments in such a way that they enclose a rectangular space, and the area of that rectangular space should be maximum possible. For example, if Monocarp …
Jul 26, 2017 · Find the length of the largest and smallest segments. In many languages (including the SAS DATA step), you would write a loop that performs these operations for each random …
It must be true for the resulting segment with $n$ marked points that all its piece have the same length distribution. Joshua Bowman has suggested that when $n=2$ calculations help realize …
Prove that there must exist 3 points such that the three line segments joining them are all red or there exist 4 points such that all 6 lines joining them are blue.
Stefan's answer is wrong because the probability of any given point on the stick being in the longest piece (when cut in 2) is not uniform. That can be seen by considering the point halfway …
Only 1 of these 4 portions will result in a triangle (since segments 4,5,6 will result in largest part being > 1/2). Ergo, 1/4 probability. Here's a nice argument: Let the length of the pieces be x, y, …
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